14=4t+.25t^2

Solution for 14=4t+.25t^2 equation:

14=4t+.25t^2

We move all terms to the left:

14-(4t+.25t^2)=0

We get rid of parentheses

-.25t^2-4t+14=0

We add all the numbers together, and all the variables

-0.25t^2-4t+14=0

a = -0.25; b = -4; c = +14;
Δ = b2-4ac
Δ = -42-4·(-0.25)·14
Δ = 30
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-4)-\sqrt{30}}{2*-0.25}=\frac{4-\sqrt{30}}{-0.5}
$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-4)+\sqrt{30}}{2*-0.25}=\frac{4+\sqrt{30}}{-0.5}
$